Question

Recognizing the no-solution case algebraically
need geometry help!!

Answer 1

"The values for y are square roots of negative numbers"

Explanation:

The steps shown are correct. But at the end we can see that we have to "take the negative square roots".

This means we have to take the square root of -1. In the real number system, we CANNOT take the square root of any negative number. Hence, there is NO SOLUTION to the system.

2nd answer choice, "The values for y are square roots of negative numbers", is right.