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If sin A = 0.31, cos A = 0.95, sin B = 0.47, and cos B 0.88, what is sin(A+B)?

If sin A = 0.31, cos A = 0.95, sin B = 0.47, and cos B 0.88, what is sin(A+B)?-example-1

2 Answers

4 votes

Answer:

0.72

Explanation:

Use the sum formula for the sine function:

sin (A + B) = sin A cos B + cos A sin B

Insert the givens into the above formula:

sin (A + B) = (0.31)(0.88) + (0.95)(0.47)

= 0.7193, or approx 0.72

4 votes

Answer:

option B

0.72

Explanation:

Given in the question,

sin A = 0.31

cos A = 0.95

sin B = 0.47

cos B = 0.88

To solve sin(A+B) we will use trigonometry identities

Compound-angle formulae

sin(A + B) = sin A cos B + cos A sin B

Plug values in above formula

(0.31) (0.88)+ (0.95) (0.47)

0.2728 + 0.4465

0.7193

≈ 0.72

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