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Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.

User Leoce
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Answer:


y^2=-8x

Explanation:

The directrix intersects the x-axis at point (2,0). Points (-2,0) and (2,0) are symmetric about the origin, so the vertex of the parabola is placed at the origin (0,0).

The parameter p of the parabola is the distance from the focus to the directrix, thus p=4.

The branches of the parabola go in negative direction of x-axis, because the focus lies to the left from the vertex.

The equation of the parabola is


(y-0)^2=-2\cdot 4\cdot (x-0),\\ \\y^2=-8x.

Find the standard form of the equation of the parabola with a focus at (-2, 0) and-example-1
User Meff
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