66.0k views
0 votes
For f(x)=3x+1 and g(x)=x^2-6, fine (f-g)(x)

User Pobk
by
7.8k points

2 Answers

5 votes

Answer:


\large\boxed{(f-g)(x)=-x^2+3x+7}

Explanation:


(f-g)(x)=f(x)-g(x)\\\\f(x)=3x+1,\ g(x)=x^2-6\\\\\text{Substitute:}\\\\(f-g)(x)=(3x+1)-(x^2-6)\\\\(f-g)(x)=3x+1-x^2-(-6)\\\\(f-g)(x)=3x+1-x^2+6\\\\(f-g)(x)=-x^2+3x+(1+6)\\\\(f-g)(x)=-x^2+3x+7

User Zgana
by
8.3k points
3 votes

Answer:

= -x^2 +3x+7

Explanation:

f-g(x)

means to subtract g(x) from f(x)

f(x)- g(x)=3x+1 -(x^2-6)

Distribute the minus sign

f(x)-g(x)= 3x+1 -x^2 +6

= 3x+7-x^2

= -x^2 +3x+7

User Darko Miletic
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories