Answer:
(A)

Explanation:
Given: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.
To find: The value of x
Solution: It is given that the circle P is circumscribed about quadrilateral ABCD and ∠BCD=120°.
Now, we know that the sum of opposite angles in a cyclic quadrilateral is 180°, therefore

substituting the given values, we get


Thus, the value of x is 60°.
Hence, option A is correct.