Question

Calculate the kinetic energy in j of an electron moving at 6.00 × 106 m/s. The mass of an electron is 9.11 × 10-28 g.

Answer 1

• The kinetic energy in J of an electron moving at 6.00 × 10⁻⁶ m/s is:

1.64 × 10 ⁻³⁸ J

Step-by-step explanation:

1) Data:

a) KE =?

b) v = 6.00 × 10⁻⁶ m/s.

c) m = 9.11 × 10⁻²⁸ g.

2) Formula:

• KE = (1/2) mv²

3) Solution:

• KE = (1/2) = (1/2) × 9.11 × 10⁻²⁸ g × ( 6.00 × 10⁻⁶ m/s)² = 163.98 × 10 ⁻⁴⁰ J

• KE = 1.64 × 10 ⁻³⁸ J

Answer 2

Answer: The kinetic energy of the electron is
`1.64* 10^(-17)J`

Step-by-step explanation:

To calculate the kinetic energy of the electron, we use the equation:

`E=(1)/(2)mv^2`

where,

m = mass of the electron =
`9.11* 10^(-28)g=9.11* 10^(-31)kg` (Conversion factor: 1 kg = 1000 g)

v = speed of the electron =
`6.00* 10^6m/s`

Putting values in above equation, we get:

`E=(1)/(2)* 9.11* 10^(-31)kg* (6.00* 10^6m/s)^2\\\\E=1.64* 10^(-17)J`

Hence, the kinetic energy of the electron is
`1.64* 10^(-17)J`