Question

A solution of SO2 in water contains 0.00023 g of SO2 per liter of solution. What is the concentration of SO2 in ppm? in ppb?

Answer 1

0.23 ppm , 230 ppb

Step-by-step explanation:

1 ppm (parts per million) is equivalent to 1 mg of SO₂ in 1 L of the water

Given mass of SO₂ = 0.00023 g = 0.00023 x 1000 mg (1g = 1000 mg) = 0.23 mg

So 0.23 mg/ L = 0.23 ppm

1 ppb (parts per billion) (10⁹) = 1000 ppm (parts per million) (10⁶)

0.23 ppm x 1000 = 230 ppb

Answer 2

= 230 ppb

Step-by-step explanation:

Considering that;

1ppm = 1mg/L

Then;

0.00023g = 0.23mg

Therefore;

0.00023 g/L = 0.23 mg/L

0.23 mg/L = 0.23 ppm

1 ppm = 100 ppb

Therefore;

0.23 ppm = 0.23 ×1000

= 230 ppb