Question

A ball is dropped from the roof of a building. If it takes 2.6s to reach the ground how tall is the building

Answer 1

33.2 m

Step-by-step explanation:

The motion of the ball is a uniformly accelerated motion, with constant acceleration g = 9.81 m/s^2 (acceleration due to gravity).

The total displacement of the ball is given by

`S=(1)/(2)gt^2`

where

t = 2.6 s is the time the ball took to reach the ground

Substituting t and g into the formula, we find the heigth of the building

`S=(1)/(2)(9.81 m/s^2)(2.6 s)^2=33.2 m`