Question

PLEASE HELP ASAP !! TANGENT RATIO

Answer 1

I will help if u help me pls

Answer 2

QUESTION 1

The tangent ratio is the ratio of the length of the opposite side to the length of the adjacent side.

`\tan(M) = (LN)/(NM)`

`\tan(M) = (8)/(6) = (4)/(3)`

QUESTION 2.

We again use the tangent ratio to find angle S.

`\tan(S) = (TU)/(SU)`

`\tan(S) = (0.75)/(3.5)`

`\tan(S) = (3)/(14)`

`S = { \tan}^( - 1) ( (3)/(14) )`

`S = 12.09 \degree`

to the nearest hundredth.

QUESTION 3

We can find CE using the tangent ratio.

`\tan(27 \degree) = (18)/(CE)`

`CE = (18)/( \tan(27 \degree) )`

`CE = 35.3 \degree`

to the nearest 0.1.