Question

What is the length of the segment with endpoints A(1,7) and B(-3, -1)?

Answer 1

Answer with Step-by-step explanation:

The length of the line segments with end point (a,b) and (c,d) is:

`√((a-c)^2+(b-d)^2)`

Here, we have to find the length of the segment with endpoints A(1,7) and B(-3, -1)

i.e. (a,b)=(1,7)

and (c,d)=(-3,-1)

Length=
`√((1+3)^2+(7+1)^2)`

=
`√(4^2+8^2)`

=
`√(16+64)`

=
`√(80)`

Hence, Length of line segment is:

`√(80)` or
`4√(5)`

Answer 2

`d = √(80) = 8.94`

Explanation:

We can find the distance using the distance formula:

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

We then substitute (1,7) as
`(x_1,y_1)` and (-3,-1) as
`(x_2,y_2)`.

`d=√((-3-1)^2+(-1-7)^2) \\d=√((-4)^2+(-8)^2) \\d=√(16+64)\\d=√(80)=8.94`