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A particle with charge 8 µC is located on the x-axis at the point −10 cm , and a second particle with charge 3 µC is placed on the x-axis at −8 cm . −10−8 −6 −4 −2 2 4 6 8 10 8 µ C 3 µ C − 3 µ C x → (cm) What is the magnitude of the total electrostatic force on a third particle with charge −3 µC placed on the x-axis at 2 cm

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Answer:Force on -7 uC charge due to charge placed at x = - 10cm

now we will have

towards left

similarly force due to -5 uC charge placed at x = 6 cm

now we will have

towards left

Now net force on 7 uC charge is given as

towards left

Step-by-step explanation:

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