Question

Helaine graphed the equation 12x – 4y = 3. What was the slope of Helaine’s line?\

Answer 1

`\large\boxed{\text{The slope}\ m=3}`

Explanation:

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept

We have the equation of a line in the standard form:

`12x-4y=3`

Convert to the slope-intercept form:

`12x-4y=3` subtract 12x from both sides

`-4y=-12x+3` divide both sides by (-4)

`y=(-12)/(-4)x+(3)/(-4)\\\\y=3x-(3)/(4)`

Answer 2

Answer: The required slope of the given line is 3.

Step-by-step explanation: Given that Helaine graphed the following equation :

`12x-4y=3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)`

We are to find the slope of the line.

We know that

the slope-intercept form of a straight line is given by

`y=mx+c,` where m is the slope of the line.

From equation (i), we have

`12x-4y=3\\\\\Rightarrow 4y=12x-3\\\\\Rightarrow y=(12x-3)/(4)\\\\\\\Rightarrow y=3x-(3)/(4).`

Comparing with the slope-intercept form, we get

slope, m = 3.

Thus, the required slope of the given line is 3.