Question

What are the zeros of the function? f(b) =b ^2 − 16b + 64

Answer 1

b = 8 and b = 8

Explanation:

f(b) =b² − 16b + 64 is set equal to zero and solved for b:

f(b) =b² − 16b + 64 = 0

This quadratic can be factored, as follows: f(b) = (b - 8)(b - 8) = (b - 8)² = 0

There are two real, equal zeros: b = 8 and b = 8.