189k views
1 vote
Let P=x^2+6
PLEASE SHOW WORK!!
15 POINTS

Let P=x^2+6 PLEASE SHOW WORK!! 15 POINTS-example-1
User Bondrak
by
7.9k points

1 Answer

3 votes

Answer:

Explanation:

P = x^2 + 6


(x^2+6)^2 - 21 = 4x^2 + 24\\(x^2+6)^2 - 4x^2 - 45 = 0

Solving for 4x^2:

P = x^2 +6

P - 6 = x^2

4(P - 6) = 4x^2

Substitution:


p^2 - 4p - 24 - 45 = 0\\p^2 -4p - 69 = 0

User Erazihel
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories