Question

Find the equation of the line that

is perpendicular to y = 6x-2 and
contains the point (6, -2).
y =
= [2²] x + [ ]

Answer 1

y = -
`(1)/(6)` x - 1

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 6x - 2 ← is in slope- intercept form

with slope m = 6

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(6)` , then

y = -
`(1)/(6)` x + c ← is the partial equation

to find c substitute (6, - 2 ) into the partial equation

- 2 = - 1 + c ⇒ c = - 2 + 1 = - 1

y = -
`(1)/(6)` x - 1 ← equation of perpendicular line