Question

What is the length of AB¯¯¯¯¯, to the nearest tenth of a centimeter?

Answer 1

13.43

Explanation:

Law of Sines

x/sin50 = 12/sin42

solve for x and don't forget to put calculator into degree mode

Answer 2

`AB\approx13.7cm` to the nearest tenth.

Explanation:

We know two angles and a given side, we can use the sine rule to find the required length.

`(AB)/(\sin(50\degree))=(12)/(\sin(42\degree))`

We solve for the AB by multiplying both sides by
`\sin(50\degree)`.

This implies that;

`AB=(12)/(\sin(42\degree))* \sin(50\degree)`

`AB=13.738`

`AB\approx13.7cm` to the nearest tenth.