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On a map, the North Carolina cities of Raleigh, Durham, and Chapel Hill form a triangle, as shown below. What are the approximate values of the missing measures on the map?

On a map, the North Carolina cities of Raleigh, Durham, and Chapel Hill form a triangle-example-1

2 Answers

5 votes

Answer: 1) r=23° , c=55° , x=10°

Explanation:

correct on edge 2020

User Jenna Kwon
by
7.7k points
5 votes

Answer

The approximate values are:

c = 55.2°

r = 22.8°

x = 9.9 miles

Explanation

- To find angle
c, we are using the rule of sines:
(a)/(sin(A)) =(b)/(sin(B)) =(c)/(sin(C))

For our triangle
a=21,A=c,b=x,B=r,c=25 and
C=102

Replacing the values we get:
(21)/(sin(c)) =(x)/(sin(r)) =(25)/(sin(102))

We can pick up two suited values to find
c:


(21)/(sin(c)) =(25)/(sin(102))


21=(25sin(c))/(sin(102))


21sin(102)=25sin(c)


sin(c)=(21sin(102))/(25)


c=sin^(-1)((21sin(102))/(25))


c=55.2

- Now that we have angle
c, we can use the angle sum theorem to find angle
r.

The angle sum theorem states the the interior angles of a triangle add up to 180°, so:


r+c+102=180


r+55.2+102=180


r+157.2=180


r=22.8

- Now that we have angle
r, we can use the rule of sines, one more time, to find side
x


(21)/(sin(c)) =(x)/(sin(r)) =(25)/(sin(102))


(x)/(sin(r)) =(25)/(sin(102))


(x)/(sin(22.8)) =(25)/(sin(102))


x=(25sin(22.8))/(sin(102))


x=9.9

User Gemma
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8.5k points