66.5k views
5 votes
Given: circle k(O), m AM=125°, m EF=31°, m∠MAF=75°. Find: m∠AME

1 Answer

4 votes

Answer:

58°

Explanation:

If m AM=125°, then m∠AOM=125°.

If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).

Thus,

m∠FOA=360°-150°-125°=85°.

If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).

Hence,

m∠EOA=m∠EOF+m∠FOA=31°+85°=116°.

Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus

m∠AME=1/2m∠EOA=58°.

Given: circle k(O), m AM=125°, m EF=31°, m∠MAF=75°. Find: m∠AME-example-1
User Sanjoy Kanrar
by
5.1k points