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A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude of the block's momentum is
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A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude of the block's momentum is

User Serberuss
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1 Answer

1 vote

Answer:

120 kg m/s

Step-by-step explanation:

The magnitude of the momentum of an object is given by


p=mv

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is


p=(10.0 kg)(12.0 m/s)=120 kg m/s

User Daniel Fone
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