Answer:
II only
Explanation:
The positive leading coefficient and even degree of f(x) tell you its graph is U-shaped and opens upward.
If there is an interval where the function is negative, it must lie between the two x-intercepts. The graph will be above the x-axis (f(x) > 0) for x-values outside that interval.
The only reasonable answer choice is ...
II (-1, 4) . . . . only