Question

Plz help me!!!!!!!!!!

Answer 1

a = ( 5 +/- sqrt(57) )/2

Explanation:

Uh...well just multiply by a and move the 4, setting the equation to 0.

a, b, and c are 2, -5, -4

Plug that into the QuadF.

Answer 2

Answer:
`\bold{(5\pm √(57))/(4)}`

Explanation:
`2a-5=(4)/(a)\\\\\text{Multiply by the LCD (a) to clear the denominator:}\\\\\\2a(a)-5(a)=(4)/(a)(a)\\\\2a^2-5a=4\\\\2a^2-5a-4=0\quad \rightarrow \quad a=2,\ b=-5,\ c=-4\\\\\\\text{Quadratic formula is: }x=(-b\pm √(b^2-4ac))/(2a)\\\\\\x=(-(-5)\pm √((-5)^2-4(2)(-4)))/(2(2))\\\\\\.\ =(5\pm √(25+32))/(4)\\\\\\.\ =(5\pm √(57))/(4)`