Question

What is the 9th term of the sequence? 3,-12,48,-192,

A. 786,432
B. -196,608
C. -786,432
D. 196,608

Answer 1

D, 196,608.

The sequence is multiplying by -4 every time.

Answer 2

Answer: The correct option is (D) 196608.

Step-by-step explanation: We are given to find the 9th term of the following sequence :

3, -12, 48, -192, . . .

Let a(n) denote the n-th term of the given sequence.

Then, a(1) = 3, a(2) = -12, a(3) = 48, a(4) = -192, . . .

We see that

`(a(2))/(a(1))=(-12)/(3)=-4,\\\\\\(a(3))/(a(2))=(48)/(-12)=-4,\\\\\\(a(4))/(a(3))=(-192)/(48)=-4,~~.~~.~~.`

So, we get

`(a(2))/(a(1))=(a(3))/(a(2))=(a(4))/(a(3))=~~.~~.~~.~~=-4.`

That is, the given sequence is a GEOMETRIC one with first term a = 3 and common ratio d= -4.

We know that

the n-th term of an geometric sequence with first term a and common ratio r is given by

`a(n)=ar^(n-1).`

Therefore, the 9th term of the given sequence is

`a(9)=ar^(9-1)=3*(-4)^8=3* 65536=196608.`

Thus, the 9th term of the given sequence is 196608.

Option (D) is CORRECT.