Question

How to solve 8(4-r)=-6(3+r)​

Answer 1

`\boxed{\bold{r=25}}`

Step By Step Explanation:

Expand
`\bold{8\left(4-r\right): \ 32-8r}`

Expand
`\bold{-6\left(3+r\right): \ -18-6r}`

Rewrite Equation

`\bold{32-8r=-18-6r}`

Subtract 32 From Both Sides

`\bold{32-8r-32=-18-6r-32}`

Simplify

`\bold{-8r=-6r-50}`

Add 6r To Both Sides

`\bold{-8r+6r=-6r-50+6r}`

Simplify

`\bold{-2r=-50}`

Divide Both Sides By -2

`\bold{(-2r)/(-2)=(-50)/(-2)}`

Simplify

`\bold{r=25}`