Question

Solve on the interval [0,2pi]

3sec x -2 = 1

Answer 1

x = 0 and x = 2π

Explanation:

We have given the equation.

3sec x -2 = 1

We have to solve it interval [0,2pi].

3sec x -2 = 1

3secx = 1+2

3secx = 3

secx = 1

x= sec⁻¹(1)

x = 0 and x = 2π is the answer in this interval.

Answer 2

Final answer is
`x=0` and
`x=2\pi`.

Explanation:

Given equation is
`3\cdot\sec\left(x\right)-2=1`

Now we need to find the solution of
`3\cdot\sec\left(x\right)-2=1` in given interval
`[0, 2\pi ]`.

`3\cdot\sec\left(x\right)-2=1`

`3\cdot\sec\left(x\right)=1+2`

`3\cdot\sec\left(x\right)=3`

`(3\cdot\sec\left(x\right))/(3)=(3)/(3)`

`\sec\left(x\right)=1`

which gives
`x=0` and
`x=2\pi` in the given interval.

Hence final answer is
`x=0` and
`x=2\pi`.