Question

Write an equation of the line that passes through (2, 0) and is perpendicular to the line

y = -x-3.
An equation of the perpendicular line is y =

Answer 1

y =x - 2

Explanation:

If the slope of the line is 'm', then the slope of the perpendicular to the given line =
`\sf (-1)/(m)` (opposite reciprocal)

y = -x - 3

Compare with equation of line in slope y-intercept form: y = mx +b

m = -1

`\sf \text{Slope of the perpendicular line = $-((1)/(-1))= 1$}`

This line passes through (2, 0);

Equation of the line in slope - point form:

`\sf y - y_1 = m(x - x_1)`

y - 0 = 1 (x - 2)

y = x - 2