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if the radius of a circle is 15 units abs the center of the circle is (-3,2), what is the equation of the circle?​

User Htbasaran
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1 Answer

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Answer:


\large\boxed{(x+3)^2+(y-2)^2=225}

Explanation:

The equation of a circle:


(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have r = 15 and the center (-3, 2). Substitute:


(x-(-3))^2+(y-2)^2=15^2\\\\(x+3)^2+(y-2)^2=225

User Louis Cremen
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