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1 vote
A jar contains 2 sugar cookies, 5 peanut butter cookies, and 3 chocolate chip cookies.What is the probability of randomly choosing a sugar cookie, not replacing it, and then choosing a peanut butter cookie?

2 Answers

3 votes

You would have 2/10 chance of choosing the sugar cookie then after you chosen it 5/9 chance of picking up a peanut butter cookie. I hope this helps

User Vivek Subramanian
by
5.7k points
3 votes

Answer:

1/9

Explanation:

The total number of cookies is

2 sugar cookies+ 5 peanut butter cookies+ 3 chocolate chip cookies= 10

We want to take a sugar cookie

P(sugar cookie) = # sugar cookie/total cookies

= 2/10 = 1/5

Now we eat the cookie (not replacing it) so there are only 9 cookies

1 sugar cookies+ 5 peanut butter cookies+ 3 chocolate chip cookies= 9

Now we want a peanut butter cookie

P(peanut butter cookie) = # peanut butter cookie/total cookies

= 5/9

To get the probability of both events happening, multiply them together

P( sugar, peanut) = 1/5 * 5/9

= 1/9

User Dyonisos
by
4.7k points
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