Question

A spring is 14cm long. Three masses are hung from it and then it is measured again. Now it is 19.5cm long. What force did the three masses provide? The spring constant for the spring is 30N/m

Answer 1

1.65 N

Step-by-step explanation:

The force applied on the spring is given by Hook's Law:

`F=k \Delta x`

where

k = 30 N/m is the spring constant

`\Delta x = 19.5 cm - 14 cm = 5.5 cm = 0.055 m` is the elongation of the spring relative to its initial position

Substituting the numbers into the equation, we find the force applied to the spring:

`F=(30 N/m)(0.055 m)=1.65 N`