225,789 views
39 votes
39 votes
What is the sum of the

HCF and
LCM of the
number
2³ x 3² x 5x7 and
2² x 5² x 11

User Rongved
by
3.2k points

1 Answer

13 votes
13 votes

Explanation:

. Find the factors of 330.

(a)2 x 4 x 5 x 11

(b)2 x 3 x 7 x 13

(c)2 x 3 x 5 x 13

(d)2 x 3 x 5 x 11

Show Answer

2. Find the factors of 1122.

(a)3 x 9 x 17 x 2

(b)3 x 11 x 17 x 2

(c)9 x 9 x 17 x 2

(d)3 x 11 x 17 x 3

Show Answer

3. 252 can be expressed as a product of primes as

(a)2 x 2 x 3 x 3 x 7

(b)2 x 2 x 2 x 3 x 7

(c)3 x 3 x 3 x 3 x 7

(d)2 x 3 x 3 x 3 x 7

Show Answer

4. Which of the following has most number of divisors?

(a)99

(b)101

(c)176

(d)182

Show Answer

5. A number n is said to be perfect if the sum of all its divisors (excluding n itself) is equal to n. An example of perfect number is

(a)6

(b)9

(c)15

(d)21

Show Answer

6. 1095/1168 when expressed in simplest form is

(a)13 / 16

(b)15 / 16

(c)17 / 26

(d)25 / 26

Show Answer

7. Reduce 128352 / 238368 to its lowest terms

(a)3/4

(b)5/13

(c)7/13

(d)9/13

Show Answer

8. The simplest reduction to the lowest terms of 116,690,151 / 427,863,887 is

(a)3/11

(b)7/11

(c)11/3

(d)None of these

Show Answer

9. The highest common factor of 0 and 6 is

(a)0

(b)3

(c)6

(d)Undefined

Show Answer

10. The H.C.F. of 2² x 3³ x 5⁵, 2³ x 3² x 5² x 7 and 2⁴ x 3⁴ x 5 x 7² x 11 is

(a)2² x 3² x 5

(b)2² x 3² x 5 x 7 x 11

(c)2⁴ x 3⁴ x 5⁵

(d)2⁴ x 3⁴ x 5⁵ x 7 x 11

Show Answer

11. The H.C.F. of 2⁴ x 3² x 5³ x 7, 2³ x 3³ x 5² x 7² and 3 x 5 x 7 x 11 is

(a)105

(b)1155

(c)2310

(d)27720

Show Answer

12. H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is

(a)180

(b)360

(c)540

(d)1260

Show Answer

13. Find the highest common factor of 36 and 84.

(a)4

(b)6

(c)12

(d)18

Show Answer

14. Even numbers are formed by taking at least two at a time from the numbers 0, 4, 8, 9. Their H.C.F. is

(a)2

(b)4

(c)10

(d)None of these

Show Answer

User Anq
by
2.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.