Question

Solve by taking the square root of both sides

Answer 1

option B

x = 1 + 3√6 or x = 1 - 3√6

Explanation:

Given in the question an equation,

3(x-1)² - 162 = 0

rearrange the x terms to the left and constant to the right

3(x-1)² = 162

(x-1)² = 162/3

(x-1)² = 54

Take square root on both sides

√(x-1)² = √54

x - 1 = ±3√6

x = ±3√6 + 1

So we have two values for x

x = 3√6 + 1 OR x = -3√6 + 1

Answer 2

b.x = 1+3√6, 1-3√6

Explanation:

We have given a quadratic equation.

3(x-1)²-162 = 0

We have to find the solution of given equation by taking the square root of both sides.

Simplifying above equation, we have

3(x-1)² = 162

Dividing above equation by 3, we have

(x-1)² = 54

Taking square root to both sides of equation, we have

x-1 = ±√54

x = ±√54+1

x = ±√(9×6)+1

x = ±3√6+1

x = 1+3√6, 1-3√6 which is the solution of given equation.