Question

The Bohr shift

The graph below shows the hemoglobin dissociation curves (also called equilibrium curves) for normal blood pH (the blue curve) and two other conditions.


Given what you know about the Bohr shift, what is the difference in O2 saturation of hemoglobin in the lungs versus hemoglobin in exercising tissues, as represented on this graph? Keep in mind that the pH of blood in the lungs is not the same as the pH of blood in exercising tissues.


Express your answer in percent


please help need ASAP

Answer 1

Th right answer is 57%

The Bohr effect is defined by the influence of pH on the dissociation curve of O2 in hemoglobin. This phenomenon is particularly interesting to study in the human body since the pH varies in the different compartments of the body.

at the pH level is relatively more alkaline than that of blood, so the dissociation curve will be deviated to the left and is represented in green in the diagram. Tissue level is the opposite, the pH is relatively more acidic than that of blood and the curve will be deviated to the right and is represented in red in the diagram.

when we extrapolate, in the lungs we have 100% oxygen hemoglobin saturation whereas at the level of the tissues it is only 43% due to the decrease of the pH and the presence of the CO2. will give 57% (100-43).