Question

SOMEBODY HELP ME PLEASE

Solve by equation by factoring. 4) x^2+11x+28=0


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Find the product. Write your answer in standard form. 5) (3a+8)(3a^2-a-7)

Answer 1

`4) \: {x}^(2) + 11x + 28 = 0 \\ \Leftrightarrow {x}^(2) + 7x + 4x + 28 = 0 \\ \Leftrightarrow x(x + 7) + 4(x + 7) = 0 \\ \Leftrightarrow (x + 4)(x + 7) = 0 \\\Leftrightarrow x = - 4 \: \vee \: x = - 7 \\ \\ 5) \: (3a + 8)(3 {a}^(2) - a - 7) \\ = 9 {a}^(3) - 3 {a}^(2) - 21a + 24 {a}^(2) - 8a - 56 \\ = 9 {a}^(3) + 21 {a}^(2) - 29a - 56`