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What are the factors of x2 − 49? (x − 1)(x + 49) (x − 7)(x − 7) (x − 7)(x + 7) Prime

User Samiya
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2 Answers

3 votes

the answer would be (x+7)(x-7)

User Hunterhacker
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Answer:

(x+7)(x-7)

The factors are -7 and 7

Explanation:

Given the function x²-49, to find the factors, we will factorise the expressed using the different of two square.

If a and b are two numbers, then based on difference of two square;

a²-b² = (a+b)(a-b)

Applying this to the function in question

x²-49

= x²-7²

= (x+7)(x-7)

The factors can be gotten by equating the function to zero according to factor theorem.

(x+7)(x-7) = 0

x+7 = 0 and x-7 = 0

x = -7 and 7

User The Lazy DBA
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