Question

What values of c and d make the equation true? Assume x>0 and y >=0.

square root of 50x^6y^3/9x^8 = 5y^c square root of 2y/dx.


A.c = 1, d = 3

B.c = 1, d = 32

C.c = 2, d = 8

D.c = 2, d = 32

Answer 1

A. c=1, d=3

Explanation:

If x>0 and y>0, then

`\sqrt{(50x^6y^3)/(9x^8)}=\sqrt{(25\cdot 2y^2\cdot y)/(9x^2)}=(5y√(2y))/(3x).`

If

`(5y√(2y))/(3x)`

is equal to

`(5y^c√(2y))/(dx),`

then

`y=y^c\Rightarrow c=1,\\ \\3x=dx\Rightarrow d=3.`