Answer:
Option D.
![y=3(x+2)^(2)+5](https://img.qammunity.org/2020/formulas/mathematics/high-school/e5esndxe2hbghcihd1285nt77z18l7w08v.png)
Explanation:
we know that
The equation of a vertical parabola in vertex form is equal to
![y=a(x-h)^(2)+k](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yubnz8asd396x2vyp3ylxb6kuv3e7wbgiy.png)
where
(h,k) is the vertex of the parabola
If a> 0 then the parabola open up and the vertex is a minimum
If a< 0 then the parabola open down and the vertex is a maximum
In this problem the vertex is the point (-2,5)
so
the equation must be equal to
and the value of a is positive
therefore
the answer is the option D