Question

`Z_(1)`=3cisπ
`Z_(2)`=5cis(π/2) If
`Z_(1)`*
`Z_(2)`=a1+b2 than a= blank, and b=blank

Answer 1

• a = 0
• b = -15

Explanation:

z1 = -3

z2 = 5i

z1·z2 = (-3)(5i) = -15i = 0 + (-15)i

Then the real and imaginary parts are a = 0, b = -15.