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How long would it take for a ball dropped from the top of a 256-foot building to hit the ground

User Liseth
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Equation for dropping a ball with 0 velocity to begin with.
We know that g is acceleration due to gravity is a constant = (-9.81 m/s^2)
V is velocity at ground
t is time to hit
Y is height dropped from

Equation:
V=(1/2)gt^2 + Y
User John Shields
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