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a teacher is holding tryouts for a school play. there are 15 students trying out for 7 parts in the play each student can play each part. in how many ways can the teacher select the students?

User Cscsaba
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1 Answer

6 votes

Answer:

6,435

Explanation:

To find the number of ways the teacher can select the students, we can use the combination formula.


_(n)C_(k)=(n!)/(k!(n-k)!)

n = 15

k = 7

Now let's plug it in.


_(n)C_(k)=(n!)/(k!(n-k)!)


_(15)C_(7)=(15!)/(7!(15-7)!)


_(15)C_(7)=(15!)/(7!8!)


_(15)C_(7)=6,435

So there are 6,435 ways that the teacher can select the students.

User Top Sekret
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