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How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?

2 Answers

3 votes

Answer: switch x and y coordinates

Explanation:

User Amertkara
by
8.0k points
4 votes

Whenever you can invert a function, you have that the graphs of
f(x) and its inverse
f^(-1)(x) are reflected with respect to the line
y=x

So, given any point on the graph of
f^(-1)(x), you can simply swap its coordinates to get the correspondent point on the original function
f(x)

As an example, all exponential functions pass through the point
(0,1), while all the logarithmic functions pass through the point
(1,0)

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