Answer:
192
Explanation:
To find how many phones are expected to be defective, we need to represent the values in a fraction.
![(x)/(8000)=(3)/(125)](https://img.qammunity.org/2020/formulas/mathematics/high-school/lbfk5icxhwx9xtmcv0cbzzknt1a3a1n0mf.png)
x = number of defective phones
Now we can solve this using algebra.
To get the value of x we need to multiply both sides by 8000 to leave x alone.
![x=(3)/(125)(8000)](https://img.qammunity.org/2020/formulas/mathematics/high-school/41cw5mg811kole8tgj7h75ibpr6srhhy4v.png)
![x=0.024(8000)](https://img.qammunity.org/2020/formulas/mathematics/high-school/pjs4b22h3k2wkizzau72d91xr11kfkeqtp.png)
![x=192](https://img.qammunity.org/2020/formulas/mathematics/high-school/s4ul16ob6yn4axpbqtct0l102z2ga6b7m8.png)
So around 192 cell phones are expected to be defective out of 8000 phones.