125k views
3 votes
CAN ANYONE HELP PLEASE??

CAN ANYONE HELP PLEASE??-example-1
User Zplizzi
by
8.4k points

1 Answer

5 votes

Answer:

Explanation:

First Question

The top question has 2 solutions because eventually you will have to take the square root of (x - 4)^2. One square root will be plus, and the other minus

(x - 4)^2 - 28 = 8 Add 28 to both sides

(x - 4)^2 -28+28 = 8+28 Collect like terms

(x - 4)^2 = 36 Take the square root.

sqrt( (x - 4)^2 ) = sqrt(36)

x - 4 = +/- 6

=============

x - 4 = + 6

x = 6 + 4

x = 10

============

x - 4 = - 6

x = - 6 + 4

x = - 2

The two solutions are (10,0) and (-2,0)

Second Question

The question is solved correctly up to the point where the square root needs to be taken. It is incorrect at that point.

x^2 - 6x - 7 = 0 Add 7 to both sides.

x^2 - 6x = 7 Add 1/2 the linear term and square it to both sides.

x^2 - 6x + (6/2)^2 = 7 + (6/2)^2 Expand the right

x^2 - 6x + 3^2 = 7 + 9

x^2 - 6x + 9 = 16 express the square on the left

(x - 3)^2 = 16 Take the sqrt of both sides.

x - 3 = sqrt(16)

x - 3 = +/-4

============

x - 3 = 4

x = 4 + 3

x = 7

===========

x -3 = - 4

x = - 4 + 3

x = - 1

==========

Solutions

(7,0) and (-1,0)

User Luca Polito
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories