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Write the equation of a line parallel to the line whose equation is 3y+5x=6 and whose y-intercept is4

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Answer:

Explanation:

Step 1: rewrite the equation of the given line in to slope-intercept form by solving for y

3y + 5x = 6

3y = -5x + 6 (subtract 5x from both sides)

y = -(5/3)x + 2 (divide both sides by 3)

Step 2: Our line is parallel to this line, so it has the same slope, and a

y-intercept of 4, so we have...

y = -(5/3)x + 4

*slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept,

User Jonathan Duarte
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