Answer:
The value of x = 0.41
Explanation:
∵

Let

∴

∴ 6y² - 5y = 6
∴ 6y² - 5y - 6 = 0 ⇒ factorize
∴ (3y + 2)(2y - 3) = 0
∴ 3y + 2 = 0 ⇒ 3y = -2 ⇒ y = -2/3
∴ 2y - 3 = 0 ⇒ 2y = 3 ⇒ y = 3/2
∵

∴
⇒ refused
(
never gives -ve values)
∵
⇒ insert ln in both sides
∵
⇒ ln(e) = 1
∴
∴ x = ln(3/2) = 0.41