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3 votes
A family on a vacation drives 123 miles in 2 hours then gets stuck in traffic and goes 4 miles in the next 15 minutes. The remaining 191 miles of the trip take 3 3/4 hours. What was their average rate of speed to the nearest tenth of a mile per hour

User Stichoza
by
6.2k points

2 Answers

3 votes

Answer:

13

Explanation:

User Amarilys
by
6.7k points
5 votes

Answer:

Their average rate of speed is 53 miles per hour.

Explanation:

Given : A family on a vacation drives 123 miles in 2 hours then gets stuck in traffic and goes 4 miles in the next 15 minutes. The remaining 191 miles of the trip take
3(3)/(4) hours.

To find : What was their average rate of speed to the nearest tenth of a mile per hour ?

Solution :

We know,
\text{Speed}=\frac{\text{Distance}}{\text{Time}}

Total distance traveled by family on vacation is

D= 123 miles + 4 miles + 191 miles = 318 miles

Total time taken by family on vacation is

T= 2 hours + 15 minutes +
3(3)/(4) hours

T= 2 hours +
(15)/(60) hours +
3(3)/(4) hours

T=
2+ (1)/(4)+ (15)/(4) hours

T=
(8+1+15)/(4) hours

T=
(24)/(4) hours

T= 6 hours

Substitute the value in the formula,


\text{Speed}=(318)/(6)


\text{Speed}=53 miles per hour.

Therefore, Their average rate of speed is 53 miles per hour.

User Alhcr
by
6.6k points
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