Question

Given that QRVTSU is a regular hexagon what are the lengths of QR and ST?

Answer 1

Explanation:

3y + 19 = 6y + 1

6y + 1 = 3y + 19

6y - 3y = 19 - 1

3y = 18

y = 6

6y + 1

6.6 + 1

37

The first one

I hope I helped you.

Answer 2

Option A. 37

Explanation:

We will understand first what is a regular hexagon?

Hexagon is a structure in which number of all the sides are 6 and since its a regular hexagon all the sides will be equal.

Since all the sides are equal and given two sides are (3y + 19) and (6y + 1)

Therefore, by the definition of regular hexagon

3y + 19 = 6y + 1

19 = 6y - 3y + 1

19 - 1 = 6y - 3y

18 = 3y

y =
`(18)/(3)=6`

Now we have to calculate the length of both the sides given.

Side ST = 6y + 1 = 6×6 + 1 = 36 + 1 = 37

and QR = 3y + 19 = 3×6 + 19 = 18 + 19 = 37

Therefore, option A. 37 is the correct answer.