Question

If f(x)=-3x+4 and g(x)=x2, what is (g°f)(0)

Answer 1

`(g\circ f)(0)=16`

Explanation:

The given functions are

`f(x)=-3x+4` and
`g(x)=x^2`

We first find the composition;
`(g\circ f)(x)`

`(g\circ f)(x)=g(f(x))`

`(g\circ f)(x)=g(-3x+4)`

`(g\circ f)(x)=(-3x+4)^2`

We now plug in x=0, to obtain;

`(g\circ f)(0)=(-3(0)+4)^2`

`(g\circ f)(0)=(4)^2`

`(g\circ f)(0)=16`

Answer 2

16

Explanation: