Question

Write an equation of the line passing through the point (5,3) with slope m = -4

Answer 1

`\large{\boxed{y-3=-4(x-5)-\text{point-slope form}}\\\boxed{y=-4x+23}}`

Explanation:

The equation of a line in point-slope form:

`y-y_1=m(x-x_1)`

m - slope

(x₁, y₁) - point

We have the slope m = -4 and the point (5, 3). Substitute:

`y-3=-4(x-5)` use distributive property

`y-3=-4x+(-4)(-5)`

`y-3=-4x+20` add 3 to both sides

`y=-4x+23`

Answer 2

Explanation:

For this problem, point slope form would be the easiest.

Point Slope Form- y-y1 = m(x-x1)

In this case, y1 is 3, x1 is 5, and m would be the slope which is -4.

y-3=-4(x-5)

This is how to write an equation for the problem.