Question

What is the speed of a beam of electrons when the simultaneous influence of an electric field of 1.56×104v/m and a magnetic field of 4.62×10−3t

Answer 1

`3.38\cdot 10^6 m/s`

Step-by-step explanation:

Assuming the electron is moving in a straight line, it means that the electric force and the magnetic force acting on the electron are balanced:

`F_E = F_B\\qE = qvB`

where

q is the electron charge

E is the electric field

v is the electron speed

B is the magnetic field

Re-arranging the equation and solving for v, we find the electron's speed:

`v=(E)/(B)=(1.56\cdot 10^4 V/m)/(4.62\cdot 10^(-3) T)=3.38\cdot 10^6 m/s`