Question

What is the standard form equation of the line shown below? (1 point) Graph of a line going through negative 2, 3 and 1, negative 3

y + 3 = −2(x − 1)
y = −2x − 1
2x + y = −1
−2x − y = 1

Answer 1

y= -2x-1

Explanation:

In solving, find the gradient from coordinates given , then use the gradient with one of the pairs to find the equation in form of y=mx+c

finding the gradient

points(-2,3) and (1,-3)

m=change in y/change in x

change in y=-3-3=-6

change in x=1--2=3

m=-6/3 =-2

taking the coordinates (1,-3) and (x,y), the equation will be

y=mx+c, where m=-2

(y--3)/(x-1) =-2

(y+3)/(x-1)= -2

(y+3) = -2(x-1)

y+3=-2x+2

y=-2x+2-3

y= -2x-1