Question

Which line represents the linear equation

–3y = 15 – 4x?

The equation –3y = 15 – 4x rewritten in slope-intercept form is .

The y-intercept is and the slope of the line is .

Line is the graph of the line –3y = 15 – 4x.

Answer 1

hopefully the photo helps

Answer 2

Pat a) The graph in the attached figure

Part b)
`y=(4/3)x-5`

The slope is
`m=(4/3)`

The y-coordinate of the y-intercept is
`b=-5`

Explanation:

Part a) Which line represents the linear equation
`-3y=15-4x`?

To graph the linear equation find the intercepts

we know that

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

`-3y=15-4(0)`

`-3y=15`

`y=-5`

The y-intercept is the point
`(0,-5)`

The x-intercept is the value of x when the value of y is equal to zero

so

For y=0

`-3(0)=15-4x`

`4x=15`

`x=15/4=3.75`

The x-intercept is the point
`(3.75,0)`

Plot the intercepts to graph the linear equation

see the attached figure

Part b) Rewritten in slope-intercept form

we know that

The equation of the line into slope intercept form is equal to

`y=mx+b`

where

m is the slope

b is the y-coordinate of the y-intercept

we have

`-3y=15-4x`

convert to slope intercept form

isolate the variable y

`3y=4x-15`

`y=(4/3)x-5`

The slope is
`m=(4/3)`

The y-coordinate of the y-intercept is
`b=-5`